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Wednesday, 13 February 2013

C PROGRAM: TO CHECK WHETHER A MATRIX IS SYMMETRIC OR NOT

CODING:
#include<conio.h>
#include<stdio.h>
void main()
{
 int a[10][10],i,j,m;
 clrscr();
 printf("Enter order of square matrix: ");
 scanf("%d",&m);
 for(i=1;i<=m;i++)
 {
  for(j=1;j<=m;j++)
  {
   printf("Enter value of a[%d][%d]: ",i,j);
   scanf("%d",&a[i][j]);
  }
 }
 for(i=1;i<=m;i++)
 {
  for(j=1;j<=m;j++)
  {
   if(a[i][j]!=a[j][i])
   {
    printf("\n\nMatrix is not symmetric");
    getch();
    exit(0);
   }
  }
 }
 printf("\n\nMatrix is symmetric");
 getch();
 }

CODING

OUTPUT

For any query or suggestion please comment below...
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5 comments:

  1. Anonymous10 February 2014 at 10:04

    thanks, really helped

    ReplyDelete
  2. Anonymous20 May 2015 at 23:32

    correction required!
    change exit() to exit(0)

    ReplyDelete
  3. zzzzz29 August 2016 at 11:19

    Thanks .. here the algorithm implemented in above program.
    1. Find transpose matrix of inputMatrix and store it in transposeMatrix.
    Check this C program to find transpose matrix
    2. Compare inputMatrix and transposeMatric.
    Check this C program to compare two matrix
    3. If both matrices are equal then inputMatrix is symmetric matrix otherwise not a symmetric matrix

    ReplyDelete
  4. Unknown16 February 2018 at 05:20

    What about the matrix with 4*4 order

    ReplyDelete